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The reaction of cyanamide, NH(2)CN(s), w...

The reaction of cyanamide, `NH_(2)CN(s)`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `-742.7 kJ mol^(-1)` at `298 K`. Calculate enthalpy change for the reaction at `298 K`.
`NH_(2)CN(g)+3/2O_(2)(g) rarr N_(2)(g)+CO_(2)(g)+H_(2)O(l)`

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`Deltan_(g)=(n_(p) -n_(p))_(g)= 2-(3)/(2) = +(1)/(2)` mol
`DeltaH =DeltaU +Deltan_(g) RT = - 742.7 kJ mol^(-1) +(+(1)/(2)mol)(8.314xx10^(-3)kJ K^(-1) mol^(-1))(298K) `
`= - 742.7 +1.2kJ mol^(-1) = - 741.5 kJ mol^(-1)`
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