For the reaction,
`2A(g)+B(g) rarr 2D(g)`
`DeltaU^(Θ)=-10.5 kJ` and `DeltaS^(Θ)=-44.1 JK^(-1)`
Calculate `DeltaG^(Θ)` for the reaction, and predict whether the reaction may occur spontaneously.

Explanation

For the given reaction,`Deltan_(g) =2- ( 3)= - 1`
`:. DeltaH^(@) =DeltaU^(@) + Deltan_(g) RT =- 10.5 kJ + ( -1) ( 8.314 xx 10^(-3) kJ ) ( 298) = - 10.5-2.48= - 12.98 kJ`
`DeltaG^(@) = DeltaH^(@)- T DeltaS=-12.98 kJ -298 ( -44.1xx 10^(-3) kJ)=-12.98 kJ+13.14 kJ =0.16 kJ `
As`DeltaG^(@) `comes out to be `+ve`,the reaction will not occur spontaneously.