Home
Class 11
CHEMISTRY
During complete combustion of one mole ...

During complete combustion of one mole of butane ,2658Kj of heat is released. The thermochemical reaction for above change is

A

`2C_(4)H_(10)(g)+13O_(2)(g) rarr 8 CO_(2)(g) +10 H_(2)O(l) Delta_(c) H=- 2658.0 kJ mol^(-1)`

B

`C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(g) Delta_(c)H=- 1329.0 kJ mol^(-1)`

C

`C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(l) Delta_(c)H=- 2658.0 kJ mol^(-1)`

D

`C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(l) Delta_(c)H=+ 2658.0 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
c
We have to take the combustion of one mole of `C_(4)H_(10)` and `Delta_(c) H` should be `-ve` and have a value of 2658 kJ mol`^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    PRADEEP|Exercise NCERT EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS( MULTIPLE CHOICE QUESTIONS-II)|5 Videos

  • THERMODYNAMICS

    PRADEEP|Exercise NCERT EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS( SHORT ANSWER QUESTIONS)|31 Videos

  • THERMODYNAMICS

    PRADEEP|Exercise NCERT SUPPLEMENTARY EXERCISE|6 Videos

  • STRUCTURE OF ATOM

    PRADEEP|Exercise Competition Focus (JEE (Main and Advanced)/Medical Entrance (IX. Assertion And Reason Type Questions (Type II))|12 Videos

Similar Questions

Explore conceptually related problems

Why does heat get released // absorbed during chemical reactions?

Volume conctraction during complete combustion of 30 ml of tolene as per reaction

During the complete combustion of methane CH_(4) , what change in hybridisation does the carbon atom undergo ?

Calculate the amount of heat evolved during the complete combustion of 100 ml of liquid benzene from the following data. (i) 18 g of graphite on complete combustion evolve 590 KJ heat (ii) 15889 KJ heat is required to dissociate all the molecules of 1 litre water into H_(2) and O_(2) (iii) The heat of formation of liquid benzene is 50 KJ//mol (iv) Density of C_(6)H_(6)(l)=0.87 g//ml