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Use the following data to calculate Delt...

Use the following data to calculate `Delta_("lattice")H^(@)` for NaBr. `Delta_("sub")H^(@)` for sodium metal = `108.4 kJ "mol"^(-1)`.Ionization enthalpy of sodium = 496`kJ "mol"^(-1)` Electron gain enthalpy of bromine = `-325 kJ "mol"^(-1)`.Bond dissociation enthalpy of bromine = 192 kJ ` "mol"^(-1)`. `Delta_(f)^(H^(@))` for NaBr (s) = `-360.1 kJ "mol"^(-1)`.

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Proceed as in calculation of lattice enthalpy for NaCl on page .
We get `Delta_("lattice") H^(@) ( NaBr)= - 360 .1 kJ mol^(-1)`
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Use the following data to calculate Delta_("lattice") H^(@) for NaBr. Delta_("sub")H^(@) for sodium metal =108.4 kJ mol^(-1) , ionization enthalpy of sodium =496 kJ mol^(-1) ., electron gain enthalpy of bromine =-325 kJ mol^(-1) bond dissociation enthalpy of bromine =192 kJ mol^(-1) , Delta _f H^(@) for NaBr(s) - 360 kJ mol^(-1) .

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