In the following questions morethan one correlation is possible between options of both columns.
Match the following `:`
`Delta`( Parameters) Description
`{:(,Delta_(r)H^(c-),Delta_(r)S^(c-),Delta_(r)G^(c-),,),((i),+,-,+,(a),"None-spontaneous at high temperature"),((ii),-,-,+ "at high T",(b),"Spontaneous at all temperatures"),((iii),-,+,-,(c ),"Non-spontaneous at all temperatures"):}`

Explanation

To solve the matching question regarding the thermodynamic parameters, we need to analyze the relationships between the enthalpy change (ΔrH), entropy change (ΔrS), and Gibbs free energy change (ΔrG) for different scenarios.

### Step-by-Step Solution:

1. **Understanding the Relationships:**
- The Gibbs free energy change is given by the equation:
\[ \Delta G = \Delta H - T \Delta S \]
- Here, ΔG indicates spontaneity:
- If ΔG < 0, the process is spontaneous.
- If ΔG > 0, the process is non-spontaneous.

2. **Analyzing Each Case:**
- **Case (i): ΔrH > 0, ΔrS < 0**
- ΔG = ΔH - TΔS
- Since ΔH is positive and ΔS is negative, ΔG will be positive (non-spontaneous).
- At high temperatures, ΔG will be even more positive, confirming that the reaction is non-spontaneous at high temperatures.
- **Match:** (i) → (a) "Non-spontaneous at high temperature"

- **Case (ii): ΔrH < 0, ΔrS < 0**
- ΔG = ΔH - TΔS
- Here, ΔH is negative and ΔS is also negative.
- At low temperatures, ΔG can be negative (spontaneous), but at high temperatures, TΔS becomes significant and ΔG becomes positive.
- Thus, at high temperatures, the reaction is non-spontaneous.
- **Match:** (ii) → (a) "Non-spontaneous at high temperature" and (c) "Non-spontaneous at all temperatures"

- **Case (iii): ΔrH < 0, ΔrS > 0**
- ΔG = ΔH - TΔS
- Here, ΔH is negative and ΔS is positive, which means ΔG will be negative (spontaneous) at all temperatures.
- **Match:** (iii) → (b) "Spontaneous at all temperatures"

3. **Final Matches:**
- (i) → (a) "Non-spontaneous at high temperature"
- (ii) → (a) "Non-spontaneous at high temperature" and (c) "Non-spontaneous at all temperatures"
- (iii) → (b) "Spontaneous at all temperatures"

### Summary of Matches:
- (i) → (a)
- (ii) → (a), (c)
- (iii) → (b)