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The enthalpy change for the reaction ,Zn...

The enthalpy change for the reaction ,`Zn (s) + 2H^(+)(aq) rarr Zn^(2+) (aq)+ H_(2)(g)`, is `-154.0kJ mol^(-1)` . The formation of 2g of hydrogen expands the system by 22.4litresat1 atm pressure. What is the internal energy of the reaction ?

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To calculate the internal energy change (ΔU) for the reaction given the enthalpy change (ΔH), we can use the relationship between ΔH and ΔU, which is expressed as: \[ \Delta H = \Delta U + P \Delta V \] Where: - ΔH is the change in enthalpy, ...
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