Sodium carbonate `(Na_(2)CO_(3)0`can be obtained by heating sodium hydrogen carbonate,`NaHCO_(3)`
`2NaHCO_(3)(s) rarr Na_(2)CO_(3)(s) +H_(2)O(g) + CO_(2)(g)`
Calculate the temperature above which `NaHCO_(3)` decomposes to form products at 1 bar .
Given `Delta_(f)H^(@) ( kJ mol^(-1)) : NaHCO_(3)(s) = =- 947.7 , Na_(2)CO_(3)(s) = - 1130 .9`,
`H_(2)O(g) = - 241.8 , CO_(2)(g) = - 393.5`
`S^(@) (JK^(-1) mol^(-1)) : NaHCO_(3)(s) = 102.1 , Na_(2)CO_(3) (s)=136.0`,
`H_(2)O(g) = 188.8, CO_(2)(g) 213.7`

Explanation

To calculate the temperature above which sodium hydrogen carbonate (NaHCO₃) decomposes to form sodium carbonate (Na₂CO₃), water (H₂O), and carbon dioxide (CO₂) at 1 bar, we will follow these steps:

### Step 1: Write the Reaction and Identify the Enthalpy Change (ΔH°)
The decomposition reaction is given as:
\[ 2 \text{NaHCO}_3(s) \rightarrow \text{Na}_2\text{CO}_3(s) + \text{H}_2\text{O}(g) + \text{CO}_2(g) \]

To find ΔH° for the reaction, we use the standard enthalpies of formation (ΔfH°) provided:
\[
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