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The enthalpy of the reaction H(2)(g)+(...

The enthalpy of the reaction
`H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g)` is `DeltaH_(1)` and that of `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)` is `DeltaH_(2)`. Then

A

`DeltaH_(1) gt DeltaH_(2)`

B

`DeltaH_(1) lt DeltaH_(2)`

C

`DeltaH_(1) = DeltaH _(2)`

D

None of these is correct

Text Solution

Verified by Experts

The correct Answer is:
b
`DeltaH_(2) gt DeltaH_(1)` because when `H_(2)O(g)` consdenseto`H_(2)O(l)`, heat of condensation is evolved.Hence, `DeltaH_(1) ltDeltaH_(2)`.
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H_(2)O(g)+(1)/(2)O_(2)(g)toH_(2)O(g)," "DeltaH=x H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)," "DeltaH=y heat of vaporization of water is:

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