`0.06` mole of `KNO_(3)` is added to `100cm^(3)` of water at `298 K`. The enthalpy of `KNO_(3)(aq)` solution is `35.8 kJ mol^(-1)`. After the solute is dissolved, the temerature of the solution will be

Options

A. 293K
B. 298K
C. 301K
D. 304 K

Answer

a

Explanation

Dissoluation of `KNO_(3)` in water is endothermic, `DeltaH _(sol) = 35.8 kJ mol^(-1)`
`:.` Heat absorbed when 0.06 mole of `KNO_(3)` is dissolved `= 35.8 xx 0.06 kJ = 2148 J`
`q= m xx c xx DeltaT`
`:. 2148 = 100 xx 4.184 xx DeltaT` or `DeltaT = 5K`
`:. `Temperature of the solution `= 298 -5= 293K`.