The amount of heat evolved when `500 cm^(3) 0.1 M HCl` is mixed with `200 cm^(3)` of `0.2 M NaOH` is

Options

A. 2.292 Kj
B. 1.292 kJ
C. `0.292kJ`
D. `3. 292 kJ`

Answer

A

Explanation

`500 cm^(3)` of 0.1 HCl `=500 xx0.1` millimole
`=50` millimole`=0.050`mole
`200 cm^(3)` of0.2 M NaOH `= 200 xx0.2` millimole
`=4` millimole
`=40`millimole
`=0.040 ` mole
Thus, 0.04 mole of NaOH neturalizes 0.04 mole of HCl.
Heat evolved from 1 mole of HCl`= 57.3 kJ`
`:.` Heat evolved from 0.04 mole of HCl `= 57.3xx 0.04 kJ=2.292kJ`