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NH(3)(g) + 3Cl(2)(g) rarr NCl(3)(g) + 3H...

`NH_(3)(g) + 3Cl_(2)(g) rarr NCl_(3)(g) + 3HCl(g), " "DeltaH_(1)`
`N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g), " "Delta H_(2)`
`H_(2)(g) + Cl_(2)(g) rarr 2HCl(g), " "Delta H_(3)`
The heat of formation of NCl3(g) in the terms of `DeltaH_(1), DeltaH_2 and DeltaH_(3)` is :

A

`DeltaH_(f) = - DeltaH_(1)+ ( DeltaH_(2))/( 2) - ( 3)/( 2) DeltaH _(3)`

B

`DeltaH_(f) = DeltaH_(1)+ ( DeltaH_(2))/( 2) - ( 3)/( 2) DeltaH _(3)`

C

`DeltaH_(f) = DeltaH_(1)- ( DeltaH_(2))/( 2) - ( 3)/( 2) DeltaH _(3)`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A
We aim at `: (1)/(2) N_(2)(g) + (3)/(2) Cl_(2)(g) rarr NCl_(3)(g), DeltaH_(f)= ?`
`(1)/(2) `Eqn. (ii) `+ (3)/(2)`Eqn. (iii) and subtracting the sum from Eqn. (i) gives the required equation. Hence,
`DeltaH _(f) = - DeltaH_(1) - [(- DeltaH_(2))/( 2) +(3)/(2) DeltaH_(3)]`
`= - DeltaH_(1) + ( DeltaH_(2))/( 2) - (3)/(2)DeltaH_(3)`
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NH_(3)(g)+3Cl_(2)toNCl_(3)(g)+3HCl(g),DeltaH_(1) N_(2)(g)+3H_(2)(g)to2NH_(3)(g),DeltaH_(2) H_(2)(g)+Cl_(2)(g)to 2HCl(g),DeltaH_(3) The heat of formation of NCl_(3) (g) in the terms of DeltaH_(1),DeltaH_(2),DeltaH_(3) is :

Given a. NH_(3)(g)+3CI(g)rarr NCI_(3)(g),3HCI(g),DeltaH_(1) b. N_(2)(g)+3H_(2)(g)rarr 2NH_(3)(g),DeltaH_(2) c. H_(2)(g)+CI_(2)(g)rarr 2HCI(g),DeltaH_(3) Express the enthalpy of formation of NCI_(3)(g)(Delta_(f)H^(Theta)) in terms of DeltaH_(1), DeltaH_(2) ,and DeltaH_(3) .

For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?

Given NH_(3)(g)+3Cl_(2)(g)toNCl_(3)(g)+3HCl(g)+x_(1) N_(2)(g)+3H_(2)(g)to2NH_(3)(g)+x_(2) H_(2)(g)+Cl_(2)(g)to2HCl(g)-x_(3) The heat of formation of NCl_(3)(g)

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