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The enthalpy of solution of sodium chlor...

The enthalpy of solution of sodium chloride is `4 kJ mol^(-1)` and its enthalpy of hydration of ion is `-784 kJ mol^(-1)`. Then the lattice enthalpy of `NaCl` (in `kJ mol^(-1)`) is

A

`+ 788`

B

`+4`

C

`+398`

D

`+780`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaH_("solution")=DeltaH _("lattice")+DeltaH_("hydration")+4= DeltaH _("lattice") +( -784)`
or `DeltaH _("lattice") =+ 788 kJmol^(-1)`
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