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Calculate the standard enthalpy change (...

Calculate the standard enthalpy change (in kJ `"mol"^(-1)`) for the reaction `H_(2)(g)+O_(2)(g)toH_(2)O_(2)(g)`, given that bond enthalpy of H-H, O=O,O-H and O-O (in kJ `"mol"^(-1)`) are respectively 438, 498, 464 and 138.

A

`-1 30`

B

`65`

C

`+130`

D

`- 334`

Text Solution

Verified by Experts

The correct Answer is:
A
`H -H(g)+O=O(g) rarr H-O-O-H(g)`
`Delta_(r)H= BE(H-H) + BE(O=O)-[2BE(O-H) +BE(O-H)]`
`=438 +498 - [2 xx 464 +138 ]kJ mol^(-1)`
`= 936- ( 928+ 138 )= - 130 kJ mol^(-1)`
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