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Enthalpy change for the reaction, 4H((g)...

Enthalpy change for the reaction, `4H_((g))rarr 2H_(2(g))` is `-869.6` kJ
The dissociation energy of H-H bond is :

A

`+217 .4kJ`

B

`-434.8 kJ`

C

`-869.6kJ`

D

`+ 434.8kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`2H_(2)(g) rarr 4H(g), DeltaH = +869.6kJ`
or `H_(2)(g) rarr 2H(g), DeltaH= + ( 869.6)/( 2) Kj`
`=434.8 kJ`
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