Home
Class 11
CHEMISTRY
When you freeze water in your freezer to...

When you freeze water in your freezer to make ice cubes,the amount of order in the molecules ofwater increases. However , second law of thermodynamics says that the amount of order in the isolated system can only stay constant or decrease with time. How can thus making of ice violate second law ?

A

because water expands during ice formation

B

because ice formation takes place at `0^(@)C`

C

because ice issolid

D

because ice cubes do not constitute isolated system.

Text Solution

AI Generated Solution

The correct Answer is:
To understand how the freezing of water into ice cubes does not violate the second law of thermodynamics, we need to analyze the concepts of order, entropy, and isolated systems step by step. ### Step-by-Step Solution: 1. **Understanding Freezing Process**: - When water freezes, it transitions from a liquid state to a solid state (ice). In this process, the molecules of water become more ordered as they arrange themselves into a crystalline structure. 2. **Change in Entropy**: - Entropy is a measure of disorder or randomness in a system. In the case of freezing, the entropy of the water decreases because the water molecules have less freedom to move in the solid state compared to the liquid state. 3. **Second Law of Thermodynamics**: - The second law states that in an isolated system, the total entropy can never decrease over time. It can only stay constant or increase. This means that the overall disorder of an isolated system should not decrease. 4. **Isolated vs. Non-Isolated Systems**: - The key point here is that the freezing of water does not occur in an isolated system. The freezer is not isolated; it exchanges heat with its surroundings. When water freezes, it releases heat to the environment, which increases the entropy of the surroundings. 5. **Entropy Change in the Surroundings**: - While the entropy of the water decreases as it freezes, the entropy of the surroundings increases due to the heat released. The total change in entropy (system + surroundings) must be considered. 6. **Conclusion**: - Therefore, even though the entropy of the water decreases when it freezes, the overall entropy of the universe (system + surroundings) increases. This is consistent with the second law of thermodynamics, which applies to isolated systems. ### Final Answer: The making of ice does not violate the second law of thermodynamics because the system (ice) is not isolated. The heat released during the freezing process increases the entropy of the surroundings, leading to an overall increase in entropy.

To understand how the freezing of water into ice cubes does not violate the second law of thermodynamics, we need to analyze the concepts of order, entropy, and isolated systems step by step. ### Step-by-Step Solution: 1. **Understanding Freezing Process**: - When water freezes, it transitions from a liquid state to a solid state (ice). In this process, the molecules of water become more ordered as they arrange themselves into a crystalline structure. 2. **Change in Entropy**: ...
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    PRADEEP|Exercise Comprehension 1|1 Videos
  • THERMODYNAMICS

    PRADEEP|Exercise Comprehension 2|2 Videos
  • THERMODYNAMICS

    PRADEEP|Exercise SHORT ANSWER QUESTIONS|65 Videos
  • STRUCTURE OF ATOM

    PRADEEP|Exercise Competition Focus (JEE (Main and Advanced)/Medical Entrance (IX. Assertion And Reason Type Questions (Type II))|12 Videos

Similar Questions

Explore conceptually related problems

Read the passage carefully and answer the question given below: Massive kind of cyber security breaches that shattered some top enterprises has raised the topic of cyber security to the forefront. Though only large companies find their way to the headlines, small businesses are not free from several cyber security threats. The horrible fact remains that the impact of cyber-attack on a small business can often be devastating. Studies by National Cyber Security Alliance show that within six months of being hacked, over 60 percent of businesses have quit the scene once for all. The most common practices to combat cyber security issues are to deploy powerful antivirus software and also to backup the data on a regular basis. This is the first step any small business can take. However, there is still a lot more to stay protected at a time when the hackers have grown technologically advanced to challenge any kind of proactive measure. Those enterprises creating easy and simple passwords like ABCD or 1234 are only facilitating a cake walk for the hackers to crack their system code. Experts advise to put some innovation in passwords including numerals, characters and alphabets. Tough passwords make it tough for hackers to crack them. Time and again remind your employees to create new and strong passwords and also change them often. Keep password attempts to minimum Most hackers try random passwords till they are able to open your account successfully. If you have implemented a six-digit pin, you are only creating a million unique possibilities and so your account is never safe. Today there are amazing passwords cracking software that can easily guess your codes within a few minutes. Therefore, keep the password attempts to minimum during every stage of the authentication process. Password management tools help create strong passwords and also remember them. So, many business wish to install them for their many advantages. However, the big downside to them is the passwords are stored in their databases making it handy for the hackers to get all of them if they can access the location just once. So, ascertion the password management tool you are depending on is reliable. Question: According to the passage, how devastating can cyber-attacks get on small firms ?

Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. For the spontaneity of a reaction, which statement is true?

PRADEEP-THERMODYNAMICS-COMPETITION FOCUS (JEE ( main andAdvanced ) /Medical Entrance Special)
  1. The direct conversion of A to B is difficult. Hence it is carried out ...

    Text Solution

    |

  2. Given an idealgas is expanded adiabatically and irreversibley form vol...

    Text Solution

    |

  3. When you freeze water in your freezer to make ice cubes,the amount of ...

    Text Solution

    |

  4. For the process H(2)O(l) to H(2)O(g) at T = 100^(@)C and 1 atmosphere ...

    Text Solution

    |

  5. one mole of an ideal gas at 300k in thermal contact with surroundings ...

    Text Solution

    |

  6. The correct thermodynamic conditions for the spontaneous reaction at a...

    Text Solution

    |

  7. For a sample of perfect gas when its pressure is changed isothermally ...

    Text Solution

    |

  8. Solutions A and B are both clear and colourles. When solution A is mi...

    Text Solution

    |

  9. The factor of DeltaG values is important in metallurgy. The DeltaG v...

    Text Solution

    |

  10. The incorrect expression among the following is

    Text Solution

    |

  11. In which of the following reactions,standard reaction entropy change(D...

    Text Solution

    |

  12. The following reaction is performed at 298 K ? 2NO(g)+O(2)(g)hArr2NO...

    Text Solution

    |

  13. Which of the following thermodynamic relation is correct?

    Text Solution

    |

  14. The densities of graphite and diamond at 298K are 2.25 and 3.31gcm^(-3...

    Text Solution

    |

  15. In view of the signs of Delta(r)G^(0) for the following reactions Pb...

    Text Solution

    |

  16. The values of DeltaH and DeltaS for the reaction, C("graphite")+CO(2...

    Text Solution

    |

  17. For a given reaction, Delta H = 35.5 kJ mol^(-1) and Delta S = 83.6 JK...

    Text Solution

    |

  18. As O2 (I) is cooled at 1 atm pressure , it freezes to form solid I at ...

    Text Solution

    |

  19. At the sublimation temperature, for the process CO(2)(S)toCO(2)(g)

    Text Solution

    |

  20. For a particular reversible reaction at temperature T, DeltaHandDeltaS...

    Text Solution

    |