one mole of an ideal gas at 300k in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant presses of 3.0 atm. In this process. The change in entropy of surrroundings `(DeltaS)` in `J^(-1)` is
(1 L atm = 101.3 J)

Options

A. 5.763
B. 1.013
C. `-1.013`
D. `-5763`

Answer

c

Explanation

As the ideal gas undergoes isothermal expansion.
`DeltaU=0`
As `q= DeltaU-W :. Q= - W`
As gas expands against constant pressure.
`W_("system") = - P DeltaV = - 3atm ( 2-1) L`
`= - 3 L atm =- 3 xx101.3 J`
`:. q_("system") = +3 xx 101.3 J`
`q_("surr") = - q_("system") = - 3 xx 101.3J`
`DeltaS_("surr.") = (q_("surr"))/(T) = ( - 3 xx 101.3J)/(300K) = -1.013J`