`{:(,"Column I( Solutions mixed)",,"Column II ( Heat evolved)"),((A),500 mL of 0.1 "M HCl acid"+200 mL of 0.2 M NaOH "solution",(p),4568J),((B),200 mLof 0.2MH_(2)SO_(4) + 400 mL of 0.5 M KOH "solution",(q),2284J),((C ),500 mL of 0.1M HCl + 500 mL of 0.1 M NH_(4)OH,(r),2760 J),((D),500 mL of 0.1 M "acetic acid " + 500 mL of 0.1 M NaOH ,(s),2575J):}`
(a) `A-r,B-p,C-s,D-q` (b) `A-p, B-r, C-q,D-s` (c ) ` A-q,B-p, C-s, D-r` (d) `A-,B-s,C-p,D-r`

Answer

c

Explanation

A. Refer to Solved Problem
B. Refer to Solved Problem
C. Enthalpy of neutralization`NH_(4)OH` with HCl`= 51.5 kJ mol^(-1)=51500 J mol^(-1)`
500mLof 0.1 M `NH_94)OH =500 xx 0.1` millimoles`=50` millimole `= 0.05` mole
`:. `Enthalpy of neutralisation.
`=51500 xx 0.05 J = 2575J`.
D. Enthalpy of neutralisation of acetic acid with NaOH `=55.2 kJ mol^(-1) = 55200 J mol^(-1)`
500mL of 0.1 M NaOh` =500 xx 0.1 ` millimole
`= 50` millimole `= 0.05 ` mole
`:. `Enthalpy ofneutralisation
`=55 200 xx 0.05 J = 2760 J`.