If vector A and B have an angle `theta` between them, then value of `|hatA -hatB|` will be

If hata and hatb are two unit vectors inclined at an angle theta , then the value of |hata-hatb| is -

If hata and hatb are two unit vectors and theta is the angle between them then vector 2hatb+hata is a unit vector if (A) theta= pi/3 (B) theta=pi/6 (C) theta=pi/2 (D) theta=pi

If hata and hatb are two unit vectors and theta is the angle between them then vector 2hatb+hata is a unit vector if (A) theta= pi/3 (B) theta=pi/6 (C) theta=pi/2 (D) theta=pi

If hata and hatb are unit vectors and theta is the angle between them show that sin (theta/2)= 1/2 |hata-hatb|

If hata and hatb are unit vectors inclined at an angle theta then prove that tan "" theta /2 = | (hata -hatb)/(hata+hatb)|

If hata and hatb are unit vectors inclined at an angle theta then prove that cos "" theta /2 = 1/2 |hata + hatb|

If |hata-hatb|= sqrt2 then calculate the value of |hata-sqrt3hatb| .