The oxide that give `H_(2)O_(2)` on treatment with dilute `H_(2)SO_(4)` is

Options

A. `PbO_(2)`
B. `BaO_(2).8H_(2)O`
C. `MnO_(2)`
D. `TiO_(2)`

Answer

B

Explanation

Oxides such as `BrO_(2), Na_(2)O_(2)`, etc. which contain peroxide linkage (i.e., `""_(-)O-O^(-)` or `O_(2)^(2-)`) on treatment with dil. `H_(2)SO_(4)` give `H_(2)O_(2)` but dioxides (O=M=O, where M is the metal atom) such as `PbO_(2), MnO_(2), TiO_(2)` do not give `H_(2)O_(2)` on treatment with dil. `H_(2)SO_(4)` .