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10 mL of a given solution of H(2)O(2) co...

`10 mL` of a given solution of `H_(2)O_(2)` contains `0.91 g` of `H_(2)O_(2)`. Express its strength in volume.

Text Solution

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68 g of `H_(2)O_(2)` produce `O_(2)=22400` mL at NTP
`therefore 0.91 g ` of `H_(2)O_(2)` will produce `O_(2)=(22400xx0.91)/(68)~= 300` mL at NTP
`therefore ` Volume strength `~=(300)/(10)~=30`
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