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Derive the structure of (i) 2-Chlorohexa...

Derive the structure of (i) 2-Chlorohexane, (ii) Pent-4-en-2-ol, (iii) 3- Nitrocyclohexene, (iv) Cyclohex-2-en-1-ol, (v) 6-Hydroxy- heptanal.

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(i) Step 1. The word root 'hex' indicates the presence of six carbon. Atoms in the chain and the primary suffix 'ane' suggests that the chain is saturated.
`C-C-C-C-C-C`
Step 2. Number the carbon atoms of the chain as indicated `overset(1)(C)-overset(2)(C)-overset(3)(C)-overset(4)(C)-overset(5)(C)-overset(6)(C)`
Step 3. The secondary prefix chloro and the numerical prefix 2 before it suggests that there is a chorine atom at position 2 as shown
`{:(overset(1)(C)-overset(2)(C)-overset(3)(C)-overset(4)(C)-overset(5)(C)-overset(6)(C)),(" |"),(" "Cl):}`
Step 4. Satisfy the tetracovalency of each carbon with required number of hydrogen atoms. Thus, the structural formula of 2-chlorohexane is
`{:(CH_(3)-CH-CH_(2)-CH_(2)-CH_(2)-CH_(2)),(" |"),(" "Cl):}`
(ii) Step 1. The word root 'pent' indicates that the longest carbon chain contains five carbon atoms. C-C-C-C-C
Step 2. Number the carbon chain as indicated. `overset(1)(C)-overset(2)(C)-overset(3)(C)-overset(4)(C)-overset(5)(C)`
Step 3. The secondary suffix-ol and the numerical prefix 2 before it suggests that there is a hydroxyl group at position 2. Therefore, fix a hydroxyl group at position 2 as shown
`{:(overset(1)(C)-overset(2)(C)-overset(3)(C)-overset(4)(C)-overset(5)(C)),(" |"),(" "OH):}`
Step 4. The primary suffix 'en' and the numerical prefix 4 before it suggests that there is a double bond at position 4. Therefore, put a double bond between positions 4 and 5 as shown.
Step 5. Satisy the tetracovalency of each carbon with the required number of hydrogen atoms. Thus, the structural formula of pent-4-en-2-ol is
`{:(overset(1)(C)H_(3)-overset(2)(C)H-overset(3)(C)H_(2)-overset(4)(C)H=overset(5)(C)H_(2)),(" |"),(" "OH):}`
(iii) Step 1. The primary prefix 'cyclo' and the word root 'hex' means that the given compound contains a six-numbered ring. Therefore, draw a cyclohexane ring as shown :

Step 2. Number the carbon atoms of the cyclohexane ring as indicated.

Step 3. The primary suffix 'en' without any numerical prefix indicates there is a double bond at position 1. Therefore, put a double bond between positions 1 and 2 as shown :

Step 4. The secondary prefix 'nitro' and the numerical prefix 3 before suggests that free is a nitro group at position 3. Therefore, place a nitro group at position 3.

This represents complete structure of 3-nitrocyclohexene.
(iv) Step 1. The primary suffix 'cyclo' and the word root hex means that the given compound contains a six-membered ring. Therefore, draw a cyclohexane ring

Step 2. Number the carbon atoms of the cyclohexane ring as indicated
Step 3. The primary suffix 2-en and the secondary suffix 1-ol indicates that there is a double bond at position 2 and an OH group at position 1. Thus, the structure of the compound cyclohex-2-en-1-ol is

(v) Step 1. The name heptanal is made up of three parts, i.e., hepi (word root) + an (primary suffix) + al (secondary suffix). This means that the given compound is an aldehyde containing 7 carbon atoms including the carbon atom of aldehyde group.
C-C-C-C-C-C-C
Step 2. Number the carbon atoms of the carbon chain is follow. `overset(7)(C)-overset(6)(C)-overset(5)(C)-overset(4)(C)-overset(3)(C)-overset(2)(C)-overset(1)(C)`
Step 3. Since aldehyde group is a chain terminating group, therefore, convert carbon at position 1 into aldehyde group as shown.
`underset(7)(C)-underset(6)(C)-underset(5)(C)-underset(4)(C)-underset(3)(C)-underset(2)(C)-underset(1)overset(O)overset(||)(C)-H`
Step 4. The secondary prefic hydroxy and the numerical prefix 6 before it indicates that there is an OH group at position 6 as shown.
`{:(" "OH" "O),(" |"" ||"),(underset(7)(C)-underset(6)(C)-underset(5)(C)-underset(3)(C)-underset(2)(C)-underset(1)(C)-H):}`
Step 5. Satisfy the tetracovalency of each carbon with the required number of hydrogen atoms. Thus, the structural formula of 6-hydroxyheptanal is
`{:(" "OH" "O),(" |"" ||"),(CH_(3)-CH-CH_(2)-CH_(2)-CH_(2)-CH_(2)-C-H):}`
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  16. Assertion: Alkyl carbonaions like ammonia have pyramidal shape. Reas...

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  18. (A) Allyl free radical is more stable than simple alkyl free radical. ...

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