The reaction, `(CH_(3))_(3)C-I overset(H_(2)O)rarr (CH_(3))_(3)C-OH` is

Options

A. elimination reaction
B. substitution reaction
C. free radical reaction
D. addition reaction.

Answer

To determine the type of reaction represented by the equation `(CH₃)₃C-I + H₂O → (CH₃)₃C-OH`, we can analyze the components and the process involved step by step.

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- The reactant is tert-butyl iodide, `(CH₃)₃C-I`, which contains three methyl groups attached to a central carbon atom and an iodine atom.
- The product is tert-butyl alcohol, `(CH₃)₃C-OH`, where the iodine atom has been replaced by a hydroxyl group (OH).

2. **Analyze the Reaction Type:**
- In this reaction, we observe that the iodine atom (I) is being replaced by a hydroxyl group (OH) from water (H₂O).
- This indicates that one functional group (iodine) is substituted by another functional group (hydroxyl).

3. **Consider the Mechanism:**
- The reaction involves the breaking of the carbon-iodine bond and the formation of a new carbon-oxygen bond.
- Since the iodine is replaced by the hydroxyl group, this process is characteristic of a substitution reaction.

4. **Elimination of Other Options:**
- **Elimination Reaction:** This would involve the removal of atoms or groups from the molecule, which is not happening here.
- **Free Radical Reaction:** There is no indication of free radicals being formed in this reaction, as it does not involve conditions like heat or light that would typically generate free radicals.
- **Addition Reaction:** This involves adding atoms or groups to a molecule without removing any, which does not apply here since we are replacing one group with another.

5. **Conclusion:**
- Based on the analysis, the reaction `(CH₃)₃C-I + H₂O → (CH₃)₃C-OH` is classified as a **substitution reaction**.

### Final Answer:
The correct answer is **B. Substitution reaction**.