Classify the following transformation according to the reaction type.
`(a) H_(3)C-CH=CH-CH_(3) + Br_(2) rarr H_(3)C - CHBr - CHBr - CH_(3)`
`(b) (H_(3)C)_(2)C = C(CH_(3))_(2) + Br_(2) rarr (H_(3)C)_(2)C = C(CH_(3))CH_(2)Br + HBr`
(c) `H_(2)C = CH - CH_(2)CH_(3) rarr H_(3)C - CH = CH - CH_(3)`
(d) `C_(6)H_(5)CHO + CH_(3)COCH_(3) rarr C_(6)H_(5)CH(OH)CH_(2)COCH_(3)`
(e) `(CH_(3))_(3)C Cl + HO^(-) rarr (CH_(3))_(2)C = CH_(2)`
`(f) {:(CH_(3)-C=N-OH+H_(3)O^(+) rarr CH_(3)-C=O),(" |"" |"),(" "Ph" "NHPh):}`

Explanation

To classify the transformations according to the reaction type, we will analyze each reaction step by step.

### (a) H₃C-CH=CH-CH₃ + Br₂ → H₃C-CHBr-CHBr-CH₃
1. **Identify the reactants**: An alkene (butene) and bromine (Br₂).
2. **Reaction type**: This is an electrophilic addition reaction. The double bond in the alkene reacts with Br₂, resulting in the addition of bromine across the double bond.

**Hint**: Look for the presence of a double bond and the addition of a halogen.

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