In the estimation of sulphur by carius method, 0.468 gm of an organic sulphur compound afforded 0.668 gm of barium sulphate. Find out the percentage of sulphur in the given compound.

Explanation

Here, the mass of the substance taken = 0.468 g
Mass of `BaSO_(4)` formed = 0.668 g
Now 1 mole of `BaSO_(4) -= 1g` atom of S or `(137 + 32 + 4 xx 16) = 233 g` of `BaSO_(4) -= 32 g` of S
Applying the relation, Percentage of sulphur `= (32)/(233) xx ("Mass of " BaSO_(4) " formed")/("Mass of substance taken") xx 100`
`= (32)/(233) xx (0.668)/(0.468) xx 100 = 19.60`.