Which of the following compounds will not exist as resonance hybrid. Give reason for your answer :
(i) `CH_(3)OH`
(ii) `R-CONH_(2)`
(iii) `CH_(3)CH=CHCH_(2)NH_(2)`

Explanation

To determine which of the given compounds will not exist as a resonance hybrid, we need to analyze each compound for the presence of resonance structures. Resonance occurs when there are multiple valid Lewis structures for a molecule that differ only in the placement of electrons, not in the arrangement of atoms.

Let's evaluate each compound:

### Step 1: Analyze `CH₃OH` (Methanol)
- Methanol consists of a hydroxyl group (-OH) attached to a methyl group (CH₃).
- There are no double bonds or lone pairs adjacent to the hydroxyl group that can participate in resonance.
- Therefore, methanol does not have any resonance structures.
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