`CH_(2)=CH^(-)` is more basic than `HC -= C^(-)`. Explain why ?

Explanation

To understand why `CH2=CH^(-)` is more basic than `HC≡C^(-)`, we need to analyze the structure and stability of the conjugate acids formed from these bases.

### Step 1: Identify the Bases
- The bases in question are `CH2=CH^(-)` (vinyl anion) and `HC≡C^(-)` (ethynyl anion).

### Step 2: Consider the Conjugate Acids
- The conjugate acid of `CH2=CH^(-)` is `CH2=CH2` (ethene), which is a stable alkene.
- The conjugate acid of `HC≡C^(-)` is `HC≡CH` (ethyne), which is a stable alkyne.
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