0.30g of an organic compound containing ...

`0.30g` of an organic compound containing `C, H`, and `O` an combustion yields `0.44g` of `CO_(2)` and `0.18g` of `H_(2) O`. If its molecular mass is `60 mu` the molecular mass is formula will be

`C_(3)H_(8)O`

`C_(2)H_(4)O_(2)`

`CH_(2)O`

`C_(4)H_(6)O`

Text Solution

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The correct Answer is:

`%C = (12)/(44) xx (0.44)/(0.30) xx 100 = 40`
`%H = (2)/(18) xx (0.8)/(0.30) xx 100 = 6.66`
`%O = 100 - (40.0 + 6.66) = 53.34`
Now `C:H:O = (40)/(12) : (6.66)/(1.0) : (53.34)/(16)`
= 3.33: 6.66 : 3.33
`:. E.F. = CH_(2)O`
E.F. wt. = 12+2+16 = 30
But Mol. wt. = 60
`:. M.F. = CH_(2)O xx (60)/(30) = C_(2)H_(4)O_(2)`

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`0.30g` of an organic compound containing `C, H`, and `O` an combustion yields `0.44g` of `CO_(2)` and `0.18g` of `H_(2) O`. If its molecular mass is `60 mu` the molecular mass is formula will be

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