Statement-1. Simple carbanions are usually pyramidal but allyl carbanion is a planar species.
Statement-2. All the carbon atoms in allyl carbanion are `sp^(2)`-hybridized.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1.
B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for statement-1.
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is False

Explanation

To analyze the statements provided, we need to understand the structure and hybridization of carbanions, particularly simple carbanions and allyl carbanions.

### Step-by-Step Solution:

1. **Understanding Carbanions**:
- Carbanions are negatively charged carbon species that have an extra electron. The geometry of carbanions is influenced by the hybridization of the carbon atom.

2. **Simple Carbanions**:
- Simple carbanions, such as methyl carbanion (CH₃⁻), have a tetrahedral geometry due to `sp³` hybridization. However, they can exhibit pyramidal geometry due to the presence of lone pairs that repel the bonding pairs of electrons.

3. **Allyl Carbanion Structure**:
- The allyl carbanion (C₃H₅⁻) consists of a carbon atom with a negative charge that is adjacent to a double bond. The structure can be represented as H₂C=CH-CH₂⁻.

4. **Hybridization of Allyl Carbanion**:
- In the allyl carbanion, the carbon atom bearing the negative charge is `sp²` hybridized. This means it has a planar structure with bond angles of approximately 120 degrees.

5. **Planarity of Allyl Carbanion**:
- The presence of `sp²` hybridization in the allyl carbanion allows for a planar arrangement of the atoms. The double bond and the negative charge contribute to this planarity.

6. **Conclusion**:
- Statement-1 is true: Simple carbanions are generally pyramidal, while the allyl carbanion is planar.
- Statement-2 is also true: All carbon atoms in the allyl carbanion are indeed `sp²` hybridized.

### Final Assessment:
Both statements are correct. Therefore, the conclusion is that both Statement-1 and Statement-2 are true.