The reaction between benzene and ICI in presence of anhyd. `AICI_3` yields _____

Answer

To solve the question regarding the reaction between benzene and iodine monochloride (ICI) in the presence of anhydrous aluminum chloride (AlCl3), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Benzene (C6H6)
- Iodine monochloride (ICI)
- Anhydrous aluminum chloride (AlCl3)

### Step 2: Understand the Role of Anhydrous AlCl3
Anhydrous AlCl3 acts as a Lewis acid in this reaction. It helps to generate a more reactive electrophile from ICI. When ICI interacts with AlCl3, it forms an electrophilic species that can react with benzene.

### Step 3: Formation of the Electrophile
When ICI is mixed with AlCl3, the aluminum chloride coordinates with the iodine in ICI, facilitating the generation of the electrophile:
\[ \text{ICI} + \text{AlCl}_3 \rightarrow \text{I}^+ + \text{AlCl}_4^- \]
Here, I+ is the electrophile that will react with benzene.

### Step 4: Electrophilic Aromatic Substitution
Benzene, being an aromatic compound, undergoes electrophilic aromatic substitution. The electrophile (I+) attacks the benzene ring, leading to the formation of iodobenzene (C6H5I) and the release of a proton (H+):
\[ \text{C}_6\text{H}_6 + \text{I}^+ \rightarrow \text{C}_6\text{H}_5\text{I} + \text{H}^+ \]

### Step 5: Final Product
The final product of the reaction between benzene and ICI in the presence of anhydrous AlCl3 is iodobenzene (C6H5I).

### Conclusion
Thus, the reaction between benzene and ICI in the presence of anhydrous AlCl3 yields **iodobenzene**.

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