Write hydrocarbon radicals that can be formed as intermediates during monochlorination of 2-methylpropane ? Which of them is more stable? Give reasons.

Explanation

2-methylpropane has two sets of equivalent hydrogens marked as 'a' and 'b' and hence gives two radicals, I and II.
`undersetI(oversetalphaCH_3-underset*oversetoversetoversetalpha(CH_3)|C-oversetalphaCH_3) larr underset"2-Methylpropane"(oversetalphaCH_3-undersetboversetoversetoverseta(CH_3)|C-oversetaCH_3) to underset"II"(CH_3-oversetoverset(CH_3)|(.^alphaCH)-oversetdotCH_2)`
Radical (I) is more stable than radical (II) because of the following two reasons :
(i)Radicals (I) is `3^@` while radical (II) is `1^@`
(ii)Radical (I) has nine `alpha`-hydrogen and hence is stabilized by nine hyperconjugation structues while radical (II) has only one `alpha`-hydrogens and is stabilized by one hyperconjugation structures as shown below :