Of the isomeric haexanes, the isomers that give the minimum and maximum number of monochloro derivatives are, respectively,

Options

A. 3-methylpentane and 2,3-dimethylbutane
B. 2,3-dimethylbutane and n-hexane
C. 2,2-dimethylbutane and 2-methylpentane
D. 2,3-dimethylbutane and 2-methylpentane

Answer

D

Explanation

`overset"(1)"CH_3-underset(.^(1)CH_3)underset|overset"(2)"CH-overset"(3)"CH_2-overset"(4)"CH_2-overset"(5)"CH_3`
2-Methylpentane has five different types of hydrogens and hence forms five monochloro derivatives. On the other hand , 2,3-dimethylbutane
`underset"(1)"CH_3-underset(._((1))CH_3)underset|overset"(2)"CH-underset"(1)"underset(CH_3)underset|overset"(2)"CH-overset"(1)"CH_3` has two different types of hydrogens and hence forms two monochloro derivatives.