`CH_3CH_3+HNO_3 overset"675 K"to` ?

Options

A. `CH_3CH_2NO_2`
B. `CH_3CH_2NO_2+CH_3NO_2`
C. `2CH_3NO_2`
D. `CH_2=CH_2`

Explanation

To solve the question regarding the reaction of ethane (CH₃CH₃) with nitric acid (HNO₃) at a temperature of 675 K, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethane (CH₃CH₃) and nitric acid (HNO₃).

### Step 2: Understand the Reaction Type
This reaction is a type of nitration, specifically known as vapor-phase nitration. In this process, ethane reacts with nitric acid to form nitroalkanes.

### Step 3: Write the Reaction Equation
When ethane reacts with nitric acid at high temperatures, the primary products are nitroethane and other nitroalkanes. The general reaction can be represented as:
\[ \text{C}_2\text{H}_6 + \text{HNO}_3 \rightarrow \text{C}_2\text{H}_5\text{NO}_2 + \text{H}_2\text{O} \]
This indicates that ethane (C₂H₆) reacts with nitric acid (HNO₃) to produce nitroethane (C₂H₅NO₂) and water (H₂O).

### Step 4: Determine the Products
The main product of this reaction is nitroethane (C₂H₅NO₂). Depending on the conditions, there may also be other nitroalkanes formed, but nitroethane is the primary product.

### Step 5: Conclusion
Thus, the reaction of ethane with nitric acid at 675 K primarily yields nitroethane.

### Final Answer:
The products of the reaction CH₃CH₃ + HNO₃ at 675 K are nitroethane (C₂H₅NO₂) and water (H₂O).

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