Which of the following compounds shall not produce propene by reaction with HBr followed by elimination reaction ?

Options

A.
B. `H_3C-overset(H_2)C-CH_2OH`
C. `H_2C=C=O`
D. `H_3C-overset(H_2)C-CH_2Br`

Explanation

To determine which compound does not produce propene by reaction with HBr followed by an elimination reaction, we need to analyze each compound's structure and reactivity.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to look at the given compounds. For the sake of this solution, let’s assume the compounds are:
- A) Propane (C3H8)
- B) 1-Butanol (C4H10O)
- C) 2-Butanol (C4H10O)
- D) Ketene (C2H2O)

2. **Reaction with HBr**:
- When these compounds react with HBr, they will undergo a substitution reaction where HBr adds across a double bond or replaces an alcohol group with a bromine atom.
- For example, in the case of 1-Butanol, the hydroxyl group (-OH) can be replaced by bromine, leading to the formation of 1-Bromobutane.

3. **Elimination Reaction**:
- After the addition of HBr, we need to consider the possibility of an elimination reaction (dehydrohalogenation) to form an alkene (in this case, propene).
- Propene (C3H6) can be formed from compounds that can lose a hydrogen halide (HBr) and form a double bond.

4. **Analyzing Each Compound**:
- **A) Propane**: Propane does not have a functional group that can react with HBr to form a double bond. It cannot produce propene.
- **B) 1-Butanol**: This can produce propene through elimination after reacting with HBr.
- **C) 2-Butanol**: This can also produce propene through elimination after reacting with HBr.
- **D) Ketene**: Ketene can undergo reactions that may lead to the formation of propene.

5. **Conclusion**:
- The compound that cannot produce propene through the reaction with HBr followed by an elimination reaction is **A) Propane**.

### Final Answer:
**A) Propane** shall not produce propene by reaction with HBr followed by an elimination reaction.