On ozonolysis , one mole of a hydrocarbon produces two molecules of ethanal and one molecule of ethanedial. The hydrocarbon could be

Options

A. 1,3-hexadiene
B. 1,4-cyclohexadiene
C. 1,4-hexadiene
D. 2,4-hexadiene

Explanation

To solve the problem, we need to identify the hydrocarbon that, upon ozonolysis, produces two molecules of ethanal (acetaldehyde) and one molecule of ethanedial (glyoxal).

### Step-by-Step Solution:

1. **Understanding Ozonolysis**: Ozonolysis is a reaction where alkenes react with ozone (O₃) to form carbonyl compounds. The products depend on the structure of the alkene.

2. **Identifying the Products**: We know that the products are:
- 2 molecules of ethanal (CH₃CHO)
- 1 molecule of ethanedial (OHC-CHO)

3. **Constructing the Reaction**:
- Since we have two molecules of ethanal and one molecule of ethanedial, we can visualize the structure of the hydrocarbon that could lead to these products.
- The presence of two ethanals suggests that the hydrocarbon likely has two double bonds.

4. **Drawing the Hydrocarbon**:
- To produce two ethanals and one ethanedial, we can consider a diene structure (a hydrocarbon with two double bonds).
- A possible structure is 2,4-hexadiene, which has the formula C₆H₁₀.

5. **Ozonolysis of 2,4-Hexadiene**:
- When 2,4-hexadiene undergoes ozonolysis, the double bonds will break, and the carbon atoms will form carbonyl groups.
- The reaction can be represented as follows:
- CH₂=CH-CH=CH-CH₂-CH₃ (2,4-hexadiene) → 2 CH₃CHO + OHC-CHO

6. **Conclusion**: The hydrocarbon that produces two molecules of ethanal and one molecule of ethanedial upon ozonolysis is 2,4-hexadiene.

### Final Answer:
The hydrocarbon could be **2,4-hexadiene**.

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