Products of the following reaction `Me_2C=CHCH_3 underset((ii)(CH_3)_2S)overset((i)O_3)to `? Are

Options

A. `CH_3CHO+CH_3COOH`
B. `Me_2CO+ CH_3CHO`
C. `Me_2CO+ CH_3COOH`
D. `2 Me_2CO`

Explanation

To solve the question regarding the products of the reaction of the alkene `Me2C=CHCH3` with ozone followed by dimethyl sulfide, we can break down the process into clear steps:

### Step 1: Identify the Alkene
The given alkene is `Me2C=CHCH3`, which can be represented as:
- A carbon-carbon double bond between the second and third carbon atoms.
- The structure can be written as:
```
CH3
|
CH3-C=C-CH3
```

### Step 2: Ozonolysis Reaction
When the alkene undergoes ozonolysis (reaction with ozone), it forms an ozonide. The double bond is cleaved, and ozone adds across the double bond.

- The ozonide formation will result in:
- One carbon from the double bond will be attached to two methyl groups (Me2C).
- The other carbon will be attached to one methyl group and one hydrogen (CH3-CH).

The ozonide structure can be represented as:
```
O
/ \
CH3-C C-CH3
\ /
O
```

### Step 3: Reduction of Ozonide
The ozonide is then treated with dimethyl sulfide ((CH3)2S), which reduces the ozonide to yield carbonyl compounds (aldehydes and ketones).

- The cleavage of the ozonide will yield:
- A ketone from the carbon with two methyl groups (Me2C) which will form acetone (CH3COCH3).
- An aldehyde from the carbon with one methyl group and one hydrogen which will form ethanol (CH3CHO).

### Step 4: Write the Final Products
The final products of the reaction can be summarized as:
- Acetone (CH3COCH3)
- Ethanal (CH3CHO)

Thus, the products of the reaction are:
1. Acetone (CH3COCH3)
2. Ethanal (CH3CHO)

### Final Answer
The products of the reaction `Me2C=CHCH3` with ozone followed by dimethyl sulfide are:
- Acetone (CH3COCH3)
- Ethanal (CH3CHO)

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