Predict the correct intermediate and product in the following reaction.
`H_(2)-C=CH overset(H_(2)O H_(2)SO_(2)) underset(H_(2)SO_(4)) to underset((A)) ("intermediante") to underset((B)) ("product")`

Options

A. `A:H_3C-undersetunderset(OH)|C=CH_2 " "B:H_3C-undersetunderset(SO_4)|C=CH_2`
B. `A:H_3C-undersetunderset(O)(||)C=CH_3 " "B:H_3C-C-=CH`
C. `A:H_3C-undersetunderset(OH)(|)C=CH_2 " "B:H_3C-undersetunderset(O)(||)C-CH_3`
D. `A:H_3C-undersetunderset(SO_4)(|)C=CH_2 " "B:H_3C-undersetunderset(O)(||)C-CH_3`

Answer

C

Explanation

Markovnikov's addition of `H_2O` occurs.
`CH_3-C-=CHunderset(HgSO_4//H_2O_4)overset(H-OH)to underset"Intermediate (A)"(CH_3-undersetunderset(OH)|C=CH_2) overset"Tautomerises"to underset"Aceton"(CH_3-undersetundersetO(||)C=CH_2)`