Identify X in the following sequence of reactions :
`CH_3-undersetunderset(Br)|CH-undersetunderset(Br)|CH-CH_2-CH_2-CH_3 underset("2.Na in liq." NH_3)overset(1. NaNH_2)to X `

Options

A. `CH_3-undersetunderset(Br)|CH-undersetunderset(NH_2)|CH-CH_2CH_2CH_3`
B.
C.
D. `CH_3-undersetunderset(NH_2)|CH-undersetunderset(NH_2)|CH-CH_2-CH_2CH_3`

Explanation

To identify the compound X in the given sequence of reactions, we will break down the process step by step.

### Step 1: Understanding the Starting Material
The starting material is:
- **CH3-CHBr-CHBr-CH2-CH2-CH3**

This compound has two bromine atoms attached to the second and third carbon atoms of a hexane chain.

### Step 2: First Reaction with Sodium Amide (NaNH2)
When we treat the compound with sodium amide (NaNH2), it acts as a strong base and facilitates an elimination reaction (E2 mechanism).

- The bromine atoms (Br) are good leaving groups. The NaNH2 will abstract a proton from the carbon adjacent to the bromine, leading to the formation of a double bond.
- The reaction will result in the formation of a triple bond between the first and second carbon atoms.

The product after this step will be:
- **CH3-C≡C-CH2-CH2-CH3**

### Step 3: Second Reaction with Sodium in Liquid Ammonia (Na in liq. NH3)
In the next step, we treat the product with sodium in liquid ammonia. This reaction typically leads to the reduction of triple bonds to double bonds, resulting in the formation of a trans-alkene.

- The triple bond between the first and second carbon atoms will be reduced to a double bond, and since sodium in liquid ammonia favors the formation of the trans isomer, we will get a trans-alkene.

The final product X will be:
- **CH3-CH=CH-CH2-CH2-CH3** (trans-alkene)

### Conclusion
Thus, the compound X after the sequence of reactions is:
- **X = CH3-CH=CH-CH2-CH2-CH3**