`CH-=CH overset(O_3)to X overset(Zn//CH_3OH)to Y`, Y is

Options

A. `CH_2OH-CH_2OH`
B. `CH_3COOH`
C. `C_2H_5OH`
D. `CH_3-CH_3`

Explanation

To solve the problem step by step, we need to analyze the reaction of acetylene (CH≡CH) with ozone (O₃) and then with zinc in methanol (Zn/CH₃OH).

### Step 1: Ozonolysis of Acetylene
- The starting compound is acetylene (CH≡CH). When acetylene undergoes ozonolysis (reaction with ozone), it forms a compound with two carbonyl groups. The ozonolysis of alkynes typically results in the formation of diketones.
- For acetylene, the ozonolysis reaction can be represented as:
\[ CH≡CH + O₃ \rightarrow CH₂=O + CH₂=O \]
This means that the product X is a compound with two carbonyl (C=O) groups, specifically, it forms formaldehyde (H₂C=O).

### Step 2: Reduction of the Dicarbonyl Compound
- The next step involves the reduction of the product X (which is two molecules of formaldehyde) using zinc in methanol (Zn/CH₃OH).
- Zinc acts as a reducing agent, providing electrons, while methanol (CH₃OH) provides protons (H⁺).
- The reduction of formaldehyde leads to the formation of a diol. The reaction can be summarized as:
\[ 2 CH₂=O + Zn/CH₃OH \rightarrow CH₂(OH)−CH₂(OH) \]
This results in the formation of ethylene glycol (also known as glycol).

### Conclusion
- Therefore, the final product Y is ethylene glycol (HO-CH₂-CH₂-OH).

### Final Answer
Y is ethylene glycol (HO-CH₂-CH₂-OH).