Statement-1. Propene reacts with HBr in presence of organic peroxide to give 1-bromopropane
Statement-2. The reaction occurs through carbocation intermediate

Options

A. Statement-1 is True, Statement-2 is True , Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True , Statement-2 is not a correct explanation for Statement-1
C. Statement- 1 is True, Statement-2 is False
D. Statement-1 is False, Statement -2 is True

Explanation

To analyze the statements provided, we need to understand the reaction of propene with HBr in the presence of organic peroxides and the mechanism involved.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
- Propene (C3H6) is an alkene that can react with hydrogen bromide (HBr).
- In the presence of organic peroxides, this reaction follows a different mechanism compared to the usual electrophilic addition.

2. **Mechanism of Reaction**:
- Normally, the addition of HBr to alkenes proceeds through a carbocation intermediate. The double bond attacks the H from HBr, forming a carbocation, which is then attacked by the Br- ion.
- However, in the presence of organic peroxides (like H2O2), the reaction follows a radical mechanism instead of forming a carbocation.

3. **Radical Mechanism**:
- The presence of peroxides generates free radicals that initiate the reaction.
- The reaction proceeds via the formation of bromine radicals, which add to the double bond of propene, leading to the formation of 1-bromopropane (instead of 2-bromopropane, which would be formed via the carbocation pathway).

4. **Conclusion**:
- **Statement-1** is true: Propene reacts with HBr in the presence of organic peroxide to give 1-bromopropane.
- **Statement-2** is false: The reaction does not occur through a carbocation intermediate; it proceeds through a radical mechanism due to the presence of organic peroxides.

### Final Answer:
- Statement-1 is true.
- Statement-2 is false.