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Copper oxide was prepared by two differe...

Copper oxide was prepared by two different methods. In case, 1.75 g of the metal gave 2. 19 g of oxide. In the second case, 1.14 g of the metal gave 1.43 g of the oxide, show that the given data illustrate the law of constant proportions.

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To demonstrate that the data illustrates the law of constant proportions, we will calculate the percentage of copper and oxygen in the copper oxide formed in both cases. The law of constant proportions states that a chemical compound always contains its component elements in fixed ratio by mass. ### Step 1: Calculate the mass of oxygen in each case **Case 1:** - Mass of copper (Cu) = 1.75 g - Mass of copper oxide (CuO) = 2.19 g - Mass of oxygen (O) in CuO = Mass of CuO - Mass of Cu = 2.19 g - 1.75 g = 0.44 g ...
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