56 g of an element M combines with 16 g of oxygen to form its oxide of type MO. Find out
(a) Equivalent mass of element
(b) Equivalent mass of oxide
(Assume law of conservation of mass to be valid).

Explanation

`underset(56 g)(M)+underset(16 g)(O)rarr underset(72 g)(MO)`
Method to calculate equivalent weight of some compounds
For Element M
`because` 16 g oxygen reacts with 56 g element M
`therefore` 8 g oxygen will react with `=(8xx56)/(16)=28`
`therefore` Equivalent mass of element = 28
For Oxide MO
`because` 16 g oxygen produce 72 g oxide
`therefore` 8 g oxygen will produce `=(8xx72)/(16)=36`
`therefore` Equivalent mass of oxide = 36.