50.0 kg of `N_(2)(g)` and 10.0 kg of `H_(2)(g)` are mixed to produce `NH_(3)(g)`. Calculate the `NH_(3)(g)` formed. Identify the limiting reagent in the production of `NH_(3)` in this situation.

Explanation

To solve the problem of how much ammonia (\(NH_3\)) is formed when mixing 50.0 kg of \(N_2(g)\) and 10.0 kg of \(H_2(g)\), we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced equation for the formation of ammonia from nitrogen and hydrogen is:
\[ N_2(g) + 3H_2(g) \rightarrow 2NH_3(g) \]

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