A sample of ammonium phosphate `(NH_(4))_(3) PO_(4)` contains 3.18 moles of hyrogen atoms . The number of moles of oxygen atoms in the sample is

Options

A. `0.265`
B. `0.795`
C. `1.06`
D. `4.00`

Answer

To find the number of moles of oxygen atoms in a sample of ammonium phosphate `(NH₄)₃PO₄` that contains 3.18 moles of hydrogen atoms, we can follow these steps:

### Step 1: Determine the composition of ammonium phosphate
The chemical formula for ammonium phosphate is `(NH₄)₃PO₄`. From this formula, we can identify:
- The number of nitrogen (N) atoms: 3
- The number of hydrogen (H) atoms: 12 (since each `(NH₄)` contributes 4 hydrogen atoms, and there are 3 of them: 3 × 4 = 12)
- The number of oxygen (O) atoms: 4

### Step 2: Establish the ratio of hydrogen to oxygen
From the formula, we know that for every 12 moles of hydrogen, there are 4 moles of oxygen. We can express this as a ratio:
- 12 moles of H : 4 moles of O

### Step 3: Calculate the moles of oxygen per mole of hydrogen
To find out how many moles of oxygen correspond to 1 mole of hydrogen, we can set up the following proportion:
- For 12 moles of H, we have 4 moles of O.
- Therefore, for 1 mole of H, the moles of O = 4 moles O / 12 moles H = 1/3 moles O.

### Step 4: Calculate the moles of oxygen for 3.18 moles of hydrogen
Now that we have the ratio of oxygen to hydrogen, we can calculate the moles of oxygen for 3.18 moles of hydrogen:
- Moles of O = (1/3) × 3.18 moles of H
- Moles of O = 3.18 / 3 = 1.06 moles of O.

### Conclusion
Thus, the number of moles of oxygen atoms in the sample is **1.06 moles**.

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