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0.5 gm of fuming H(2)SO(4) (Oleum) is di...

0.5 gm of fuming `H_(2)SO_(4)` (Oleum) is diluted with water. This solution is completely neutralised by 26.7 ml of 0.4 M `NaOH` solution. Calculate the percentage of free `SO_(3)` in the given sample. Give your answer excluding the decimal places.

A

Mass of `SO_(3)` is 0.104 g

B

% of free `SO_(3) = 20 : 7`

C

Normality of `H_(2) SO_(4)` for neutralization is 0.2 N

D

Weight of `H_(2) SO_(4)` is 0.104 g

Text Solution

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The correct Answer is:
A, B
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