Photoelectrons are removed with kinetic energy `1.864 xx 10^(-21)J`, when photons of light with energy ` 4.23 xx 10^(-19) J` fall on the metal. What is the minimum energy required per mole to remove an electron potassium metal?
Hing`: hv_(0)= hv-KE`
Energy required per mole `=hv_(0) xx 6.022 xx 10^(23)`

Explanation

To find the minimum energy required per mole to remove an electron from potassium metal, we can follow these steps:

### Step 1: Understand the relationship between photon energy, kinetic energy, and minimum energy required to remove an electron.
The equation provided in the hint is:
\[ hv_0 = hv - KE \]
Where:
- \( hv_0 \) is the minimum energy required to remove an electron from the metal.
- \( hv \) is the energy of the incoming photon.
...