Home
Class 12
CHEMISTRY
STATEMENT-1 : The de-Broglie wavelength...

STATEMENT-1 `:` The de-Broglie wavelength of an electron decreases as kinetic energy decreases.
and
STATEMENT- 2 `:` The de-Broglie wavelength `lambda= ( h)/(sqrt( 2mKE))`

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 isTrue, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False , Statement-2 isTrue

Text Solution

Verified by Experts

The correct Answer is:
4
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -F) Matrix - Match Type Questions|4 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -G) Integer Answer Type Questions|4 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -D) Linked Comprehension Type Questions)|9 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION -D) Assertion-Reason Type Questions|15 Videos

  • SURFACE CHEMISTRY

    AAKASH INSTITUTE|Exercise Assignment Section - C (Assertion - Reason type questions)|10 Videos

Similar Questions

Explore conceptually related problems

The de-Broglie wavelength lamda

de-Broglie wavelength lambda is

Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV.

Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV.

The de Broglie wavelength is given by

The de-Broglie wavelength of an electron in the first Bohr orbit is

The de Broglie wavelength lambda of a particle

The de-Broglie wavelength associated with an electron having a kinetic energy of 10 eV is

The de-Broglie wavelength is proportional to