Home
Class 12
CHEMISTRY
Magnetic momentum of an ion M^(+3) is sq...

Magnetic momentum of an ion `M^(+3)` is `sqrt( 35)` BM. Then, number of electron in d orbital of M element will be `"___________"`

Text Solution

Verified by Experts

The correct Answer is:
6
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -H) Multiple True - False Type Questions|5 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -I) Subjective Type Questions|7 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -F) Matrix - Match Type Questions|4 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION -D) Assertion-Reason Type Questions|15 Videos

  • SURFACE CHEMISTRY

    AAKASH INSTITUTE|Exercise Assignment Section - C (Assertion - Reason type questions)|10 Videos

Similar Questions

Explore conceptually related problems

Magnetic moment of M^(x+) is sqrt(24)BM . The number of unpaired electrons in M^(x+) is.

Spin magnetic moment of X^(n+) (Z=26) is sqrt(24) B.M. Hence number of unpaired electrons and value of n respectively are:

Magnetic moment of X^(3+) ion of 3d series is 2sqrt6 BM. What is the atomic number of X ?

The magnetic moment of M^(+) (atomic number = 25 is sqt(15) BM .The number of unpaired electron and the value of x respectivekly are

What is orbital angular momentum of an electron in 3d orbital.

For d electron, the orbital angular momentum is

The magnetic moment of an ion in its +3 oxidation state is 3.85 BM . The number of unpaired electrons present in the ions is

The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is

Magnetic moment of X^(+3) ion of 3d series is sqrt(35)B.M What is the atomic number of X^(+3) ?