Calculate the enthalpy change where the standard heat of formation for gaseous `NH_(3)` is -11.02 kcal/mol at 298 K. The reaction given is
`(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g) rarr NH_(3)(g)`

Explanation

To calculate the enthalpy change (ΔH) for the given reaction:

\[ \frac{1}{2} N_2(g) + \frac{3}{2} H_2(g) \rightarrow NH_3(g) \]

we will use the standard heat of formation for gaseous ammonia (NH₃), which is given as -11.02 kcal/mol at 298 K.

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