Home
Class 12
CHEMISTRY
Heat of neutralisation of oxalic acid is...

Heat of neutralisation of oxalic acid is -53.35 kJ/g.eq. using NaOH. Calculate the value of `Detla`H for the given reaction `H_(2)C_(2)O_(4) hArr C_(2)O_(4)^(2-) + 2H^(+)`

Text Solution

Verified by Experts

7.9 kJ/mol
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise SECTION-J|7 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise Exercise|50 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise SECTION-H|3 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise Assignment (SECTION - D) (ASSERTION-REASON TYPE QUESTION)|20 Videos

Similar Questions

Explore conceptually related problems

The heat of neutralisation of oxalic acid is -25.4 kcal mol^(-1) using strong base, NaOH . Hence, the enthaly change of the process is H_(2)C_(2)O_(4) hArr 2H^(o+) +C_(2)O_(4)^(2-) is

Heat of neutralisation of oxalic acid is -106.7 KJ mol^(-1) using NaOH hence Delta H of : H_(2)C_(2)O_(4)rarr C_(2)O_(4)^(2-)+2H^(+) is :-

Heat of neutralization between HCl and NaOH is -13.7 kcal "equiv"^(–1) . Heat of neutralization of H_2C_2O_4 (oxalic acid) with NaOH is -26 kcal mol^(-1) . Hence, heat of dissociation of H_(2)C_(2)O_(4) as H_2C_2O_(4) rarr 2H^(+) + C_(2)O_(4)^(2-) , is :

Statement-I : The enthalpy of neutralization of the reaction between HCl and NaOH is -13.7 kCal/mol. If the enthalpy of neutralization of oxalic acid (H_(2)C_(2)O_(4)) by a strong base is -25.4 kCal/mol, then the enthalpy change (|Delta_(r)H|) of the process H_(2)C_(2)O_(4) rarr 2H^(+)+C_(2)O_(4)^(2-) is 11.7 kCal/mol. Statement-II : H_(2)C_(2)O_(4) is a weak acid.

Calculate the number of molecules of exalic acid (H_(2)C_(2)O_(4)2H_(2)O) in 100 mL of 0.2 N oxalic acid solution.