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pH is the negative logarithm of H^(+) ...

pH is the negative logarithm of `H^(+)`
` pH=log[H^(+)]`
`HCllt H^(+)+Cl^(-)`
`H_(2)OhArrH^(+)+OH^(-)`
` K_(W)=[H^(+)][OH^(-)]`
`K_(W)` depend on the temperatue. With rise in temperature `K_(W)` increases.
At 298 K, pH of pure water = 7
The exact concentration of `H^(+)` in `10^(-6)` M HCl given by

A

`10^(-6)+10^(-8)`

B

`10^(-6)+10^(-7)`

C

`10^(-6)`

D

`10^(-6)-10^(-7)`

Text Solution

Verified by Experts

The correct Answer is:
B
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